Question

Vă rog exercițiul nr. 31
Mulţumesc ,

Answer 1

5,4=54/10=27/5

4,5=45/10=9/2

cele 10 nr consecutive:

a, a+1; a+2; ….; a+9

{a; a+9} i.p.{ 27/5; 9/2}

27a/5=9(a+9)/2

2•27a=5•9•(a+9) /:9

6a=5a+45 => a=45

45+46+47+….+54=(45+54)•10/2=99•5=495