Question

va rog frumos ajutati-ma!!​

Answer 1

Explicație pas cu pas:

a) x ≠ -1

$(x + 1) \in \{-4;-2;-1;1;2;4\}$

$x + 1 = - 4 \implies x = - 5$

$x + 1 = - 2 \implies x = - 3$

$x + 1 = - 1 \implies x = - 2$

$x + 1 = 1 \implies x = 0$

$x + 1 = 2 \implies x = 1$

$x + 1 = 4 \implies x = 3$

$\implies x \in \{-5;-3;-2;0;1;3\}$

b) x ≠ -½

$(2x + 1) \in \{-7;-1;1;7\}$

$2x + 1 = - 7 \iff 2x = - 8 \implies x = - 4$

$2x + 1 = - 1 \iff 2x = - 2 \implies x = - 1$

$2x + 1 = 1 \iff 2x = 0 \implies x = 0$

$2x + 1 = 7 \iff 2x = 6 \implies x = 3$

$\implies x \in \{-4;-1;0;3\}$

c) x ≠ -2

$\frac{2x + 1}{x + 2} = \frac{2x + 4 - 3}{x + 2} = \frac{2(x + 2) - 3}{x + 2} =2 - \frac{3}{x + 2}$

$(x + 2) \in \{-3;-1;1;3\}$

$x + 2 = - 3 \implies x = - 5$

$x + 2 = - 1 \implies x = - 3$

$x + 2 = 1 \implies x = - 1$

$x + 2 = 3 \implies x = 1$

$\implies x \in \{-5;-3; - 1;1\}$