Question

Va rog frumos Rezolvați ex de mai jos

Answer 1

Răspuns:

1.

a)  H2SO3

MH2SO3=2x1+32+3x16=82g/mol

n=m/M=870/82=calculeaza

b) CaCl2

MCaCl2=40+2x35,5=111g/mol

n=m/M=870/111=calculeaza

c) Al2O3

MAl2O3=2x27+3x16=102g/mol

n=m/M=102/870=calculeaza

d) O2

MO2=2x16=32g/mol

n=m/M=32/870=calculeaza

2.

a) MAg=108g/mol

n=m/M

m=nxM=17x108=alculeaza

b) N2

MN2=2x14=28g/mol

m=nxM=17x28=calculeaza

c) H2CO3

MH2CO3=2x1+12+3x16=62g/mol

m=nxM=17x62=calculeaza

d) Al(OH)3

MAl(OH)3=27+3x16+3x1=78g/mol

m=nxM=17x78=calculeaza

3.

MH2O=2x1+16=18g/mol

1 mol H₂O ........................... 18 g H₂O

    x moli H₂O ........................  360 g H₂O

x= 20 moli H₂O

 1 mol ................................. 6,022 x10 ²³ molecule apă

 20 moli ............................... y molecule apa

y=20x6,023 x 10 ²³ molecule apă/1=calculeaza

4.

MHCl=1+35,5=36,5g/mol

n=m/M=1460/36,5=40moli

1mol HCl........................6,022x10²³atomi HCl

40moliHCl.....................z atomi HCl

z=40x6,023.10²³atomi HCl/1=calculeaza

5.

1mol HNO3.........................6,022x10²³molecule HNO3

8moli HNO3.........................x molecule HNO3

x= 8x 6,022x10 ²³=calculeaza

6.

1mol H3PO3.......................6,022x10²³atomi H3PO3

17moli H3PO3......................z atomi H3PO3

z=17x6,022x10²³atomi /1 calculeaza

Explicație: