Question

va rog mult!!!!!!!!!​

Answer 1

Explicație pas cu pas:

Regula : a^m × a^n = a^m+n

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a). 3^7 × 3^4=3^10

b). 2^6 × 2^4 x 2=2^10 × 2=2^11

c). 7^14

d). 11^100

e). 2^5x

f). 13^5a+5b

g). 5^100

h). 7^1 × 7^2 × 7^3 × ........ ×7^100 = 7^1+2+3+...+100=7^5050

Aplicam suma gauss

n(n+1):2=100(100+1):2=100 × 101 : 2=10100 :2= 5050

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Sper ca te-am ajutat!!

Answer 2

$\it a)\ \ 3^7\cdot3^4=3^{7+4}=3^{11}\\ \\ b)\ \ 2^6\cdot2^4\cdot2=2^{6+4+2}=2^{11}\\ \\ c)\ \ 7^8\cdot7^6=7^{8+6}=7^{14}\\ \\ d)\ \ 11^{53}\cdot11^{47}=11^{53+47}=11^{100}\\ \\ e)\ \ 2^{2x}\cdot2^{3x}=2^{2x+3x}=2^{5x}=(2^5)^x=32^x$