Question

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Dau coroana!

(3x+4)la puterea a2 + 19=119

Answer 1

(3x+4)^2+19=119
(3x+4)^2=119-19
(3x+4)^2=100
3x+4=10
3x=10-4
3x=6
x=2
proba:(3*2+4)^2+19=(6+4)^2+19=10^2+19=100+19=119

Answer 2

$(3x+4)^{2} + 19 = 119$
$9x^{2} + 12x + 12x +16 +19 = 119$
$9x^{2} + 24x + 16 + 19 = 119$
$9x^{2} +24x + 35 = 119$
$9x^{2} +24x +35-119=0$
$9x^{2} +24x-84=0$
$x_{1,2}= \frac{-24+/- \sqrt{576-4*9*(-84)} }{2*9} = \frac{-24+/- \sqrt{576+3024} }{18} = \frac{-24+/- \sqrt{3600} }{18}$
$x_{1}= \frac{-24+60}{18} = \frac{36}{18} =2$
x=2