Question

Va rog repede!! Ajutati.ma va rog

Answer 1

sper ca te.am ajutat!

Answer 2

a) x(x-4+x)=x(2x-4)=2x²-4x=2x(x-2)
b)2x(3x-5)=6x²-10x
c)3x(x²-6+x)=3x³-18x+3x²=3x³+3x²-18x⇔3x²(x+1)-18x
d)2x³(5x²-2x+3)=15x⁵-4x⁴+6x³
e)x/4 (x-x/2)=x/4 ori 2x-x/2=x/4 ori x/2=x²/8
f)(3+x)(x-6)=3x-18+x²-6x=-3x-18+x²=x²-3x-18
g)(x-1)(3x-3)=3x²-3x-3x+3=3x²-6x+3=3(x-1)²
h)(8+x)(2x-6)=16x-48+2x²-6x=2x²+10x-48=2(x²-5x+24)
i) (6x²-1)(3x-3)=18x³-18x²-3x+3<=>18x²(x-1)-3(x-1)<=>(x-1)(18x²-3)
j)(x²-1)(x⁴+x²+1)=x⁶+x⁴+x²-x⁴-x²-1=x⁶-1
k)4x(2x-3)-3x(2x+1)=8x²-12x-6x²-3x=2x²-15x
eu asa stiu...