Question

Va rog repede dau coroana!!
(3y-2)(2+3y)​

Answer 1

(3y-2)(2+3y)=

=(3y-2)(3y+2)=

=(3y) la puterea a doua - 2 la puterea a doua=

(Folosim (a-b)(a+b)=a la a doua - b la a doua, pt. a restrange produsul)

=9y la puterea a doua - 4

Answer 2

Răspuns:

$(3y - 2)(2 + 3y) = 6y + 9y {}^{2} - 4 - 6y = 9y {}^{2} - 4 \\ 9y {}^{2} - 4 = 0 \\ 9y {}^{2} = 4 \\ y {}^{2} = \frac{4}{9} \\ y1 = - \frac{2}{3} \\ y2 = \frac{2}{3}$