Question

Va rog sa ma ajutati ​

Answer 1

Răspuns:

$5 \sqrt{2} (3 \sqrt{8} - 5 \sqrt{32} + 7 \sqrt{50} - 13 \sqrt{72} ) \\ \\ 5 \sqrt{2} (3 \sqrt{4 \times 2} - 5 \sqrt{4 \times 8} + 7 \sqrt{25 \times 2} - 13 \sqrt{9 \times 8}) \\ \\ 5 \sqrt{2} (3 \times 2 \sqrt{2} - 5 \times 2 \sqrt{8} + 7 \times 5 \sqrt{2} - 13 \times 3 \sqrt{8} ) \\ \\ 5 \sqrt{2} (6 \sqrt{2} - 25 \sqrt{8} + 35 \sqrt{2} - 39 \sqrt{8} ) \\ \\ 5 \sqrt{2} (6 \sqrt{2} - 25 \sqrt{4 \times 2} + 35 \sqrt{2} - 39 \sqrt{4 \times 2} ) \\ \\ 5 \sqrt{2} (6 \sqrt{2} - 25 \times 2 \sqrt{2} + 35 \sqrt{2} - 39 \times 2 \sqrt{2} ) \\ \\ 5 \sqrt{2} (6 \sqrt{2} - 50 \sqrt{2 } + 35 \sqrt{2} - 78 \sqrt{2} ) \\ \\ 5 \sqrt{2} \times 41 \sqrt{2} - 128 \sqrt{2} \\ \\ 205 \times 2 - 128 \sqrt{2} \\ \\ 410 - 128 \sqrt{2} \\ \\ 2(205 - 64 \sqrt{2} )$