Question

Va rog sa mi explicați cum s ar putea rezolva ,mulțumesc

Answer 1

[tex]\it \lim\limits_{x \to 0} \dfrac{ln(1+ex)}{x} \ \stackrel{\frac{0}{0}}{=} \lim\limits_{x \to 0} \dfrac{[ln(1+ex)]'}{x'} = \lim\limits_{x \to 0} \dfrac{\dfrac{e}{1+ex}}{1}= \\ \\ \\ = \lim\limits_{x \to 0} \dfrac{e}{1+ex} = \dfrac{e}{1} =e[/tex]