Question

Valorie lui x in functor de :

Answer 1

Răspuns:

(3x+4)/(2x+1)€Z inmultim cu 2 =>

2(3x+4)/(2x+1)€ Z=>

(6x+8)/(2x+1 )€Z=>

(6x+3+5)/(2x+1) €Z=>

3(2x+1)+5 / 2x+1 €Z =>

3(2x+1)/2x+1 +(5/2x+1) € Z=>

3 +(5/2x+1)€Z,dar 3 € Z=>

5/2x+1€Z=> 2x+1€ D5 => 2x+1€{;-5;-1;1;5}

1)2x+1=-5 => x=-3

2)2x+1=-1 => x=-1

3)2x+1=1 => x=0

4)2x+1=5 => x=2