Question

(7⁵×8³)²:(2⁹×7¹⁰)=
(2⁹+2⁹+2⁹)⁵:(81×2⁴⁵)=​

Answer 1

Răspuns:

1 . ( 7^5× 8^3) ^2÷(7×14^9)

( 7^5 ×8^3)^2 supra 7×14^9

(7^2×56^3)^2 supra 7×14^9

7^4×56^6 supra 7×14^9

7^3×2^12×14^6supra 14^9

7^3×2^12supra 14^3

7^3×2^12supra 2^3×7^3

2^9

2.(3×2^9)^5÷(81×2^45)

(3×2^9)^5supra 81×2^45

243×2^45supra 81× 2^45

243supra 81

3

^---- putere

Answer 2

Răspuns:

$\bf \big( 7^5 \cdot 8^3\big)^2 : \big(2^{9} \cdot {7}^{10} \big) =$

$\bf \big( 7^{5 \cdot2} \cdot 8^{3 \cdot2}\big) : \big(2^{9} \cdot {7}^{10} \big) =$

$\bf \big[ 7^{10} \cdot (2^{3} )^{6}\big] : \big(2^{9} \cdot {7}^{10} \big) =$

$\bf \big( 7^{10} \cdot 2^{3\cdot 6}\big) : \big(2^{9} \cdot {7}^{10} \big) =$

$\bf \big( 7^{10} \cdot 2^{18}\big) : \big(2^{9} \cdot {7}^{10} \big) =7^{10-10} \cdot 2^{18-9}=$

$\bf 7^{0} \cdot 2^{9}= 1 \cdot 2^{9}= \red{\underline{~ 2^{9}~}}$

                                     

$\bf \big( 2^9+2^9+2^9\big)^5 : \big(81 \cdot {2}^{45} \big) =$

$\bf \big( 2^9\cdot 3\big)^5 : \big(3^{4} \cdot {2}^{45} \big) =$

$\bf \big( 2^{9\cdot5} \cdot 3^5\big) : \big(3^{4} \cdot {2}^{45} \big) =\big( 2^{45} \cdot 3^5\big) : \big(3^{4} \cdot {2}^{45} \big) =$

$\bf 2^{45-45} \cdot 3^{5-4}=2^{0} \cdot 3^{1}=1\cdot 3=\purple{\underline{3}}$

==pav38==