Question

a) 4×(×-5)-14=50;
b)[12+3×(2×+1)] =24;
c)[(3×-2)×5-1]:2+5=7
dau coroana
[3+4×(6x-1)]:47+9=10;​

Answer 1

Răspuns:

a) 4×(5×)-14=50

4×5×-14=50

20×-14=50

20×=50+14

20×=64

X= 16/ 5

b) 12+6×+3=24

15+6×=24

6×=24-15

6×=9

×= 3/2

c) (15×-10-1)÷2+5=7

15×-11÷2+5=7

15×-11÷2+5=7

15×-11 totul supra 2 +5=7

15×-11+10=14

15×-1=14

15×=14+1

15×=15

X= 1

d) 3+ 24X-4 ÷47+9=10

(-1+24×)÷47+9=10

-1+24×totul Supra 47 +9=10

-1 +24×+423=470

422+24×=470

24×=470-422

24×=48

×= 2