Question

alculeaza:
a) 5×(2×5+1)-4×5+ 1;
b) 5 + 5×(9 +3×4);
c) (7×2 + 4)-15-11×14;
d) 7×[5×3-(4×3-5)] + 3×4;
e) (2 + 2×3)^2:2^4;
f) (5^2+10×5^2):11​

Answer 1

a) 5×(2×5+1)-4×5+ 1+=5x(10+1)-20+1=5x11-20+1=55-20+1=36

b) 5 + 5×(9 +3×4)=5+5x(9+12)=5+5x21=5+105=110

c) (7×2 + 4)-15-11×14=(14+4)-15-154=18-15-1545=-151

d) 7×[5×3-(4×3-5)] + 3×4=7x[15-(12-5)]+12=7x(15-7)+12=7x8+12=56+12=68

e) (2 + 2×3)^2:2^4=(2+6)^2:2^4=8^2:2^4=2^6:2^4=2^2=4

f) (5^2+10×5^2):11​=11x5^2:11=1x5^2=25

Answer 2

Răspuns:

A) 5*(2*5+1)-4*5+1=36

B) 5+5*(9+3*4)=110

C) (7*2+4)-15-11*14=151

D) 7*[5*3-(4*3-5)]+3*4 =68

E)(2+2*3)*2:2*4=33

F)(5*2+10*5*2):11=54

Sper ca te-am ajutat