Question

Am pus o poza cu problema 5.1.6 si cum am incercat sa o rezolv, puteti sa imi spuneti ce am gresit? mersi

Answer 1

Lucram in ml, e mai usor la calcule
notam: a ml de propan si b ml etan
22,4ml.............3*22,4ml
C3H8 + 5O2 -> 3CO2 + 4H2O
a ml.................3a ml
22,4ml...................2*22,4ml
C2H6 + 7/2 O2 -> 2CO2 + 3H2O
b ml.......................2b ml
a+b=25 => a=25-b
3a+2b=60 => 3(25-b)+2b=60 => 75-b=60 => b=15ml
a=25-15=10ml
25ml........100%
15ml............x% => x=15*100/25=60%
10ml............y% => y=10*100/25=40%
raportul molar=raportul volumetric mereu!!! (Caci n=V/Vm, si cum Vm e o valoare constanta intr-un raport se simplifica si ramane raportul volumetric)
VC3H8:VC2H6=15/10=3/2