Question

calculează 2 1 supra 2 - [ 3 supra 4 - ( 1- 5 supra 8 )].b) 3 1supra 4 +[1 1supra 4 +[ 1 1 supra 6 - ( 1 - 1 supra 12 )] c) ( 1 1supra 3 - 1 1supra 5 ) + [ 2 - ( 1 - 1 supra 15 )] d) [ 1 + ( 1 - 2 supra 3 )] - ( 2 - 1 supra 6 - 1 1supra 3 ).​

Answer 1

a)

$\frac{21}{2} - ( \frac{3}{4} - (1 - \frac{5}{8}) = \frac{21}{2} - ( \frac{3}{4} - \frac{8 - 5}{8} )) = \frac{21}{2} - ( \frac{3}{4} - \frac{3}{8} )) = \frac{21}{2} - \frac{3}{8} = \frac{81}{8}$

b)

$\frac{31}{4} + ( \frac{11}{4} + ( \frac{11}{6} - (1 - \frac{1}{12} ))) = \frac{31}{4} + ( \frac{11}{4} + ( \frac{11}{6} - \frac{11}{12} = \frac{31}{4} + ( \frac{11}{4} + \frac{11}{12} ) = \frac{31}{4} + \frac{11}{3} = \frac{137}{12}$

c)

$( \frac{11}{3} - \frac{11}{5} ) + (2 - (1 - \frac{1}{15} )) = \frac{22}{15} + (2 - \frac{14}{15} ) = \frac{22}{15} + \frac{16}{15} = \frac{38}{15}$

d)

$(1 + (1 - \frac{2}{3} )) - (2 - \frac{1}{6} - \frac{11}{3} ) = (1 + \frac{1}{3} ) - ( - \frac{11}{6} ) = \frac{4}{3} + \frac{11}{6} = \frac{19}{6}$