Question

cum descompui 2x²+3x-3​

Answer 1

$2x^2+3x-3 \\ \\ \Delta = (-3)^2-4\cdot 2\cdot(-3) = 9+24 = 33 = (\sqrt{33})^2 \\ \\ x_{1,2} = \dfrac{-3\pm \sqrt{33}}{4} \\ \\\\ 2x^2+3x-3 = 2\Big(x-\dfrac{-3-\sqrt{33}}{4}\Big)\Big(x-\dfrac{-3+\sqrt{33}}{4}\Big) = \\ \\ = 2\Big(x+\dfrac{3+\sqrt{33}}{4}\Big)\Big(x-\dfrac{\sqrt{33} - 3}{4}\Big)$