Question

Determinati numerele reale a si b, a<b, stiind ca  $a+b=a^{2} +b^{2} =1$

Answer 1

Rezolvarea e atasata.

Answer 2

a^2+b^2= (a+b)^2-2ab=1-2ab

1-2ab= 1

2ab=0

Daca a=0, b=1

Daca b=0, a=1.

Deci, solutiile sunt {(0,1),(1,0)}