Question

log in baza 9 a lu ∛1/3=?

Answer 1

$log_{9} \sqrt[3]{ \frac{1}{3} } = x$

$9^{x} = \sqrt[3]{ \frac{1}{3} }$

$(3^{2}) ^{x} = \sqrt[3]{ 3^{-1} }$

$3^{2x} = ( 3^{-1} )^{ \frac{1}{3} }$

$3^{2x} = 3^{ \frac{-1}{3} }$

$2x = \frac{-1}{3}$

$x = \frac{ \frac{-1}{3} }{2} = - \frac{1}{6}$

Answer 2

Log in baza 9 a lu 1/3= -1/6 nu am copiat de la celalalt raspuns ci am facut pe foaie... Acasa. . Sper ca te-am ajutat...