Question

ofer 40 de puncte!! ajutor!​

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

Explicație pas cu pas:

1.b)

${( - 32 {x}^{4} )}^{5} : {( - 16 {x}^{3} )}^{6} = ( {( - {2}^{5} )}^{5} {x}^{4 \cdot 5} ) : ({( - {2}^{4} )}^{6} {x}^{3 \cdot 6} ) =$

$= (- {2}^{25} {x}^{20} ) : ({2}^{24} {x}^{18} ) = (- {2}^{25} : {2}^{24}) \cdot ({x}^{20} : {x}^{18})$

$= - {2}^{25 - 24} \cdot {x}^{20 - 18} = \bf - 2 {x}^{2}$

6.a)

$\mathcal{A_{4}} = {\ell}^{2} = 25 \cdot {a}^{2} {b}^{2} {c}^{4}$

$\ell = \sqrt{25 \cdot {a}^{2} {b}^{2} {c}^{4}} = 5 \cdot a b {c}^{2}$

$\mathcal{P_{4}} = 4 \cdot \ell = 4 \cdot 5 a b {c}^{2} = \bf 20 a b {c}^{2}$

b)

$\mathcal{P_{4}} = 4 \cdot \ell = 24 \cdot a {b}^{2} {c}^{3}$

$\ell = \dfrac{24 \cdot a {b}^{2} {c}^{3}}{4} = 6 \cdot a {b}^{2} {c}^{3}$

$\mathcal{A_{4}} = {\ell}^{2} = {(6 \cdot a {b}^{2} {c}^{3})}^{2} = \bf 36 {a}^{2} {b}^{4} {c}^{6}$