Question

suma a trei numere impare consecutive este 405.care sunt numerele?

Answer 1

$a+a+2+a+4=405 \\ \\ 3a+6=405 \\ \\ 3a=405-6 \\ \\ 3a=399 \\ \\ a=399:3 \\ \\\boxed{ a=133} \\ \\ a+2=133+2=135 \\ \\ a+4=133+4=137 \\ \\ \boxed{R:[133,135,137]}$

Answer 2

[tex]a+a+2+a+4=405 \\ 3a+6=405|-6 \\ 3a=399|:3 \\ \boxed{a=133} \\ \boxed{a+2=135} \\ \boxed{a+4=137}[/tex]