Question

tg$\pi$-cos²$\frac{ \pi }{6} +ctg \frac{ \pi }{3}$

Answer 1

$tg \pi =0;cos^2 \frac{ \pi }{6}=( \frac{ \sqrt{3} }{2})^2 = \frac{3}{4};ctg \frac{ \pi }{3}= \frac{1}{ \sqrt{3} }=[tex] \frac{ \sqrt{3} }{3}$ \\ tg \pi -cos^2 \frac{ \pi }{6} +ctg \frac{ \pi }{3}=- $\frac{ \sqrt{3}-3 }{12}$