Question

Un turist parcurge un traseu in 4 zile astfel: in prima zi parcurge un sfert din traseu, a doua zi jumatate din cat i-a ramas, a 3a zi un sfert din noul rest si in a4a zi restul de 200 km.
a)Aflati lungimea traseului
b) Aflati cat a parcuras inn fiecare zi

Answer 1

x=km traseu
x/4=ziua 1
x-x/4=3x/4 =rest
3x/4*1/2=3x/8 =ziua 2
3x/4-3x/8=3x/8=rest
3x/8*1/4=3x/32 =ziua 3
x/4+3x/8+3x/32+200=x
8x+12x+3x=6400=32x
9x=6400
x=711,(1) km traseu
x/4=711,(1):4=177,(7)  km ziua1
711,1-177,(7)=533,(3)
533,(3):2=266,(6) km ziua 2
266,(6):4=66,(6) km ziua 3
266,(6)-66,6)=200 km ziua 4

Answer 2

prima zi⇒x/4;
a ramas x-x/4=4x/4-x/4=3x/4;
a doua zi⇒3x/4 ·1/2=3x/8;
a ramas 3x/4-3x/8=6x/8-3x/8=3x/8;
a treia zi⇒3x/8 ·1/4=3x/32;
a ramas 3x/8-3x/32=12x/32-3x/32=9x/32;
⇒9x/32=200⇒x=32·200/9=711,[1][km-lungimea traseului];⇒la punctul a;
b. prima zi⇒177,[7][km];
a doua zi]⇒266,[6][km];
a treia zi⇒66,[6][km];
a patra zi⇒200km;